33=-47x^2+4x+33

Solution for 33=-47x^2+4x+33 equation:

33=-47x^2+4x+33

We move all terms to the left:

33-(-47x^2+4x+33)=0

We get rid of parentheses

47x^2-4x-33+33=0

We add all the numbers together, and all the variables

47x^2-4x=0

a = 47; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·47·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*47}=\frac{0}{94}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*47}=\frac{8}{94}
=4/47
$